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h^2-9h-70=0
a = 1; b = -9; c = -70;
Δ = b2-4ac
Δ = -92-4·1·(-70)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-19}{2*1}=\frac{-10}{2} =-5 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+19}{2*1}=\frac{28}{2} =14 $
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